How do you solve by substitution 5x-6y=65x6y=6 and 5x+y=25x+y=2?

2 Answers
Apr 29, 2018

y=-4/7y=47
x=18/35x=1835

Explanation:

5x-6y=65x6y=6 --- (1)
5x+y=25x+y=2 --- (2)

(1) minus (2)

-6y-y=6-26yy=62
-7y=47y=4
y=-4/7y=47 --- (3)

Sub (3) into (1)

5x-6times-4/7=65x6×47=6
5x+24/7=65x+247=6
5x=18/75x=187
x=18/35x=1835

Apr 29, 2018

The solution is (18/35,-4/7)(1835,47) or (0.514,-0.571)(0.514,0.571).

Explanation:

Solve the system of equations.

"Equation 1":Equation 1: 5x-6y=65x6y=6

"Equation 2":Equation 2: 5x+y=25x+y=2

The solution to the system of linear equations is the point they have in common, the point of intersection. The system will be solved using substitution.

Solve Equation 2 for yy.

y=-5x+2y=5x+2

Substitute -5x+25x+2 for yy in Equation 1. Solve for xx.

5x-6(-5x+2)=65x6(5x+2)=6

Expand.

5x+30x-12=65x+30x12=6

Simplify.

35x-12=635x12=6

Add 1212 to both sides.

35x=6+1235x=6+12

Simplify.

35x=1835x=18

Divide both sides by 3535.

x=18/35x=1835 or 0.5140.514

Substitute 18/351835 for xx in Equation 2. Solve for yy.

5(18/35)+y=25(1835)+y=2

Simplify color(red)cancel(color(black)(5))^1(18/color(red)cancel(color(black)(35))^7) to 18/7.

18/7+y=2

Multiply both sides by 7.

color(red)cancel(color(black)(7))^1xx18/color(red)cancel(color(black)(7))^1+7xxy=2xx7

Simplify.

18+7y=14

Subtract 18 from both sides.

7y=14-18

Simplify.

7y=-4

Divide both sides by 7.

y=-4/7 or -0.571

Solution

(18/35,-4/7) or (0.514,-0.571)

graph{(y-5/6x+1)(y+5x-2)=0 [-10, 10, -5, 5]}