How do you solve by substitution $x = y - 1$ $x = y - 1$ and $y = 4 - 2 x$ $y = 4 - 2x$ ?

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How do you solve by substitution $x = y - 1$ $x = y - 1$ and $y = 4 - 2 x$ $y = 4 - 2x$ ?

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Answer 1 · 2015-06-08T14:16:10

${x = y - 1$ ${x=y-1$
${y = 4 - 2 x$ ${y=4-2x$
Substitute for $x$ $x$ into the second equation:
$y = 4 - 2 (y - 1)$ $y=4-2(y-1)$
$y = 4 - 2 y + 2$ $y=4-2y+2$
$3 y = 6$ $3y=6$
$y = 2$ $y=2$
Back into the first equation:
$x = 2 - 1 = 1$ $x=2-1=1$
Solution
$x = 1$ $x=1$
$y = 2$ $y=2$

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How do you solve by substitution $x = y - 1$ $x = y - 1$ and $y = 4 - 2 x$ $y = 4 - 2x$ ?

1 Answer

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Science

Math

Humanities

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How do you solve by substitution x=y−1x = y - 1 and y=4−2xy = 4 - 2x?

1 Answer

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Impact of this question

How do you solve by substitution $x = y - 1$ $x = y - 1$ and $y = 4 - 2 x$ $y = 4 - 2x$ ?