How do you solve by substitution $x + y = 4$ $x + y = 4$ and $y = 2 x + 1$ $y = 2x + 1$ ?

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How do you solve by substitution $x + y = 4$ $x + y = 4$ and $y = 2 x + 1$ $y = 2x + 1$ ?

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Answer 1 · 2015-06-08T14:56:21

${x + y = 4$ ${x+y=4$
${y = 2 x + 1$ ${y=2x+1$
Take the second and substitute into the first for $y$ $y$ :
$x + (2 x + 1) = 4$ $x+(2x+1)=4$
$3 x = 3$ $3x=3$
$x = 1$ $x=1$
Back into equation 2:
$y = 2 + 1 = 3$ $y=2+1=3$
Solution:
$x = 1$ $x=1$
$y = 3$ $y=3$

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How do you solve by substitution $x + y = 4$ $x + y = 4$ and $y = 2 x + 1$ $y = 2x + 1$ ?

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How do you solve by substitution x+y=4x + y = 4 and y=2x+1y = 2x + 1 ?

1 Answer

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Impact of this question

How do you solve by substitution $x + y = 4$ $x + y = 4$ and $y = 2 x + 1$ $y = 2x + 1$ ?