How do you solve #C=12dq# for d?

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Answer 1 · 2016-10-30T00:44:24

#d = C/(12q)#

To solve for #d# you must remove #12# and #q# from the right side of the equation while keeping the equation balanced.

#C/12 = (12dq)/12#

#C/12 = (12/12)dq#

#C/12 = 1*dq#

#C/12 = dq#

#C/(12q) = (dq)/q#

#C/ (12q) = d*(q/q)#

#C/(12q) = d * 1#

#d = C/(12q)#