How do you solve #(cos x - 1)(cos x - 4) = 0# over the interval 0 to 2pi?
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"How do I solve #y'' + y = -2 sin(x)# with the initial conditions #y(0) = 0# and #y'(0) = 1#?"
1 Answer
Feb 5, 2016
Hence
so we have that
