How do you solve #e^(x-1)-5=5#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Alan N. Aug 22, 2016 #x~=3.30258# Explanation: #e^(x-1) -5 =5# #e^(x-1) = 10# #x-1 = ln10# #x-1 ~= 2.30258# #x~= 3.30258# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 5477 views around the world You can reuse this answer Creative Commons License