How do you solve for a in #2a - b = ac + 3b#?
1 Answer
Apr 25, 2018
Explanation:
#"collect terms in a on the left side of the equation"#
#"and all other terms on the right side"#
#"add b to both sides"#
#2acancel(-b)cancel(+b)=ac+3b+b#
#rArr2a=ac+4b#
#"subtract "ac" from both sides"#
#2a-ac=cancel(ac)cancel(-ac)+4b#
#rArr2a-ac=4b#
#"factor out the a on the left side"#
#rArra(2-c)=4b#
#"divide both sides by "(2-c)#
#(acancel((2-c)))/cancel(2-c)=(4b)/(2-c)#
#rArra=(4b)/(2-c)#