How do you solve for c in #a(c - b) = d#?

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Answer 1 · 2016-05-04T21:07:52

#c = d/a+b# unless #a=0#...

Case #bb(a = 0)#

If #a=0# then #a(c-b) = 0# regardless of the value of #c#.

Hence:

Case #bb(a != 0)#

If #a!=0# then we can divide both sides of the equation by #a# to get:

#c-b = d/a#

Then add #b# to both sides to find:

#c = d/a+b#