How do you solve for do in $\frac{h i}{h o} = - \frac{d i}{d o}$ $(hi)/(ho)=-(di)/(do)$ ?

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How do you solve for do in $\frac{h i}{h o} = - \frac{d i}{d o}$ $(hi)/(ho)=-(di)/(do)$ ?

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Answer 1 · 2016-09-03T07:11:53

$(d o) = - \frac{h o \times d i}{h i}$ $(do) = -(ho xx di)/(hi)$

Explanation:

If an equation has one fraction on each side, you can get rid of the denominators by cross-multiplying.

$\frac{h i}{h o} = - \frac{d i}{d o}$ $(hi)/(ho) = -(di)/(color(red)(do))$

$h i \times d o = - h o \times d i \leftarrow \div (h i)$ $hixxcolor(red)(do) = -ho xx di " "larr div "(hi)$

$d o = - \frac{h o \times d i}{h i}$ $color(red)(do) = -(ho xx di)/(hi)$

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If an equation has one fraction on each side, you can invert the whole equation. This will put $d o$ $do$ in the numerator.

$\frac{h o}{h i} = - \frac{d o}{d i} \leftarrow \times - d i$ $(ho)/(hi) = - (color(red)(do))/(di)" "larr xx -di$

$- \frac{h o \times d i}{h i} = d o$ $-(ho xx di)/(hi) =color(red)(do)$

$d o = - \frac{h o \times d i}{h i}$ $color(red)(do) = -(ho xx di)/(hi)$

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How do you solve for do in $\frac{h i}{h o} = - \frac{d i}{d o}$ $(hi)/(ho)=-(di)/(do)$ ?

1 Answer

Explanation:

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How do you solve for do in hiho=−dido(hi)/(ho)=-(di)/(do) ?

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Explanation:

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How do you solve for do in $\frac{h i}{h o} = - \frac{d i}{d o}$ $(hi)/(ho)=-(di)/(do)$ ?