How do you solve for k in #3k+6t=b+5#?
1 Answer
May 3, 2016
Explanation:
Isolate the k term on the left side and place all other terms on the right.
hence : 3k = b + 5 - 6t
Now divide both sides by 3 to obtain k.
#rArr(cancel(3) k)/cancel(3)=(b+5-6t)/3 =1/3(b+5-6t)#
