How do you solve for m in $K=1/2 m^2$ ?

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Answer 1 · 2016-08-29T06:48:13

$m= (2*K)^0.5$

Let me compute m step by step.

$m^2 = 2*K$

Now square root both sides:

$m = (2*K)^0.5$

Answer 2 · 2016-08-29T06:55:10

$m = +-sqrtK$

Isolate m, step by step. This is also called making $m$ the subject of the formula.

It feels more comfortable to have $m$ on the left hand side. We may just turn the equation around to achieve this.

$K = 1/2 m^2$

$1/2 m^2 = K color(white)(............................................) xx2$

$cancel2 xx 1/cancel2 m^2 = K xx2$

$m^2 = Kcolor(white)(............................................) "find" sqrt$

$m = +-sqrtK$

How do you solve for m in K=1/2 m^2K=1/2 m^2?