How do you solve for x: #7/12(x-3)=1/3x+4#?

2 Answers
Jun 30, 2018

#x=23#

Explanation:

Multiplying the given equation by #12#

#7(x-3)=12/3x+48#

#7(x-3)=4x+48#

since
#7(x-3)=7x-21#

we get

#7x-21=4x+48#

Adding #21#

#7x=4x+69#

subtracting #4x#

#3x=69#
so

#x=23#

Jun 30, 2018

#x=23#

Explanation:

Let's get rid of the fractions so we can just have a plain vanilla linear equation. We can multiply all terms by #12#. We get

#7(x-3)=4x+48#

We can next distribute the #7# to both terms in the parenthesis to get

#7x-21=4x+48#

Next, we can add #21# to both sides to further isolate the #x# terms. We will get

#7x=4x+69#

Subtracting #4x# from both sides gives us

#3x=69#

Lastly, we can divide both sides by #3# to get

#x=23#

Hope this helps!