How do you solve for x in #A= 3/4 (p) (a+x)#?

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Answer 1 · 2016-03-18T14:54:31

#x = (4A )/(3p) - a #

#A = color(blue)((3/4))* (p) (a+x) #

#A * color(blue)((4/3)) = color(green)((p)) (a+x) #

#4/3 A = color(green)((p)) * (a) + color(green)((p)) * (x) #

#(4A)/3 = pa + px #

#(4 A)/3 = color(purple) (p) * ( a+ x) #

#(4A )/(3 * color(purple)(p)) = a+ x #

#(4A )/(3p) = a+ x #

#(4A )/(3p) - a = x #