How do you solve for x in $C = b - b x$ $C=b-bx$ ?

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Answer 1 · 2017-02-10T13:26:26

See the entire solution process below:

First, subtract $b$ $color(red)(b)$ from each side of the equation to isolate the $x$ $x$ term while keeping the equation balanced:

$C - b = b - b x - b$ $C - color(red)(b) = b - bx - color(red)(b)$

$C - b = b - b - b x$ $C - b = b - color(red)(b) - bx$

$C - b = 0 - b x$ $C - b = 0 - bx$

$C - b = - b x$ $C - b = -bx$

Now, divide each side of the equation by $- b$ $color(red)(-b)$ to solve for $x$ $x$ while keeping the equation balanced:

$\frac{C - b}{- b} = \frac{- b x}{- b}$ $(C - b)/color(red)(-b) = (-bx)/color(red)(-b)$

$(C - b)/color(red)(-b) = (color(red)(cancel(color(black)(-b)))x)/cancel(color(red)(-b))$

$(C - b)/-b = x$

$x = (C - b)/-b$

Or

$x = C/-b - b/-b$

$x = -C/b + b/b$

$x = -C/b + 1$

$x = 1 - C/b$

How do you solve for x in C=b-bxC=b−bxC=b-bx?