How do you solve for x in C=b-bxC=bbx?

1 Answer
Feb 10, 2017

See the entire solution process below:

Explanation:

First, subtract color(red)(b)b from each side of the equation to isolate the xx term while keeping the equation balanced:

C - color(red)(b) = b - bx - color(red)(b)Cb=bbxb

C - b = b - color(red)(b) - bxCb=bbbx

C - b = 0 - bxCb=0bx

C - b = -bxCb=bx

Now, divide each side of the equation by color(red)(-b)b to solve for xx while keeping the equation balanced:

(C - b)/color(red)(-b) = (-bx)/color(red)(-b)Cbb=bxb

(C - b)/color(red)(-b) = (color(red)(cancel(color(black)(-b)))x)/cancel(color(red)(-b))

(C - b)/-b = x

x = (C - b)/-b

Or

x = C/-b - b/-b

x = -C/b + b/b

x = -C/b + 1

x = 1 - C/b