How do you solve for x: in #x - 8 + x = 1 - 4x #?

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Answer 1 · 2018-05-16T22:17:53

#x = 3/2#

#x - 8 + x = 1 - 4x#

#x - 9 + x = -4x#

#x - 9 = -5x#

#6x = 9#

#x = 9/6#

#x = 3/2#

Opposite operation on like terms on either side to bring all #x# terms and integer terms onto opposite sides of the equals.