How do you solve for x in #x+k/ j = 3/4 #?

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Answer 1 · 2017-08-11T02:11:16

See a solution process below:

Subtract #color(red)(k/j)# from each side of the equation to solve for #x#:

#x + k/j - color(red)(k/j) = 3/4 - color(red)(k/j)#

#x + 0 = 3/4 - k/j#

#x = 3/4 - k/j#

If you need the right side of the equation over a common denominator then multiply each fraction by the appropriate form of #1#:

#x = (j/j xx 3/4) - (4/4 xx k/j)#

#x = (3j)/(4j) - (4k)/(4j)#

#x = (3j - 4k)/(4j)#