How do you solve for x?: ${log}_{6} (36) = 5 x + 3$ $log_6 (36) = 5x + 3$

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Answer 1 · 2015-10-21T17:41:54

$x = - \frac{1}{5}$ $x=-1/5$

Using the definition of logs, together with laws of exponents, we may write this equation in exponential form as

$6^{5 x + 3} = 36$ $6^(5x+3)=36$

$therefore6^(5x)*6^3=6^2$

$therefore5x+3=2=>-1/5$

How do you solve for x?: log_6 (36) = 5x + 3log6(36)=5x+3log_6 (36) = 5x + 3