How do you solve for x: $\frac{x - 3}{4} + \frac{x}{2} = 3$ $(x-3) /4 + x/2 =3$ ?

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How do you solve for x: $\frac{x - 3}{4} + \frac{x}{2} = 3$ $(x-3) /4 + x/2 =3$ ?

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Answer 1 · 2016-08-18T08:08:40

$x = 5$ $x = 5$

Explanation:

In an equation with fractions, we can get rid of the denominators by multiplying each term by the LCD (LCM of denominators).
IN this case the LCM is $4$ $color(red)4$

$color(red)cancel4xx((x-3)) /cancel4 + color(red)cancel4^2xx x/cancel2 =color(red)4xx3$

$x-3 +2x = 12$

$3x =15$

$x =5$

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How do you solve for x: $\frac{x - 3}{4} + \frac{x}{2} = 3$ $(x-3) /4 + x/2 =3$ ?

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Explanation:

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How do you solve for x: $\frac{x - 3}{4} + \frac{x}{2} = 3$ $(x-3) /4 + x/2 =3$ ?