How do you solve for y $5x+6y-12=0$ ?

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Answer 1 · 2018-03-17T21:15:18

$y = -5/6 x + 2$

We start with:

$5x+6y-12 = 0$

To isolate $y$ , we begin by transferring terms that do not contain $y$ to the opposite side of the equation.

First, let's subtract $5x$ from both sides:

$5x color{orange}{-5x}+6y-12=0color{orange}{-5x}$

$=> 6y - 12 = -5x$

Now let's add $12$ to both sides:

$6y - 12 color{orange}{+12}= -5x color{orange}{+12}$

$=> 6y = -5x+12$

Now that all the $y$ terms and non $y$ terms are on opposite sides, we can solve for $y$ .

We just need to divide by $6$ on both sides:

$6ycolor{orange}{-:6}= -5xcolor{orange}{-:6}+12color{orange}{-:6}$

$=> color{blue}{y = -5/6 x + 2}$

How do you solve for y 5x+6y-12=05x+6y-12=0?