Question

How do you solve for y in `1+7y=5x-2`?

Answer 1

`y=5/7x-3/7`

Explanation:

Isolate 7y on the left side of the equation by subtracting 1 from both sides.

`cancel(1)cancel(-1)+7y=5x-2-1`

`rArr7y=5x-3`

divide both sides by 7

`(cancel(7) y)/cancel(7)=1/7(5x-3)`

`rArry=1/7(5x-3)" or "`

`y=5/7x-3/7`