How do you solve for y in #3x+2y= 12#?

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Answer 1 · 2015-04-07T05:22:54

The answer is #y=-3/2x+6#.

#3x+2y=12#

Subtract 3x from both sides.

#2y=12-3x#

Divide both sides by 2.

#(cancel(2)y)/(cancel(2))=(12)/(2)-(3)/(2)x# =

#y=6-3/2x#

#y=-3/2x+6#

If this is meant to be the equation for a line in slope-intercept form, #-3/2# is the slope, and #6# is the y-intercept.