How do you solve for y in #-3x+5y=-10#? Algebra Graphs of Linear Equations and Functions Slope-Intercept Form 1 Answer Don't Memorise Apr 11, 2015 #-3x+5y=-10# As we need to solve for #y#, we transpose #-3x# to the right hand side to get #5y=-10 + 3x# We divide both sides by 5 #(cancel(5)y)/cancel(5)=(-10 + 3x)/5# #y = - 10/ 5 + (3x)/5# #y = - 2 + (3x)/5# #color(green)(y = (3x)/5 - 2# Answer link Related questions What is Slope-Intercept Form? How do you find the "m" and "b" of any linear equation? How do you determine the slope and y intercept when given a graph? Why is slope "rise over run"? How do you find the slope and y intercept of #2x+5=y#? What is the slope and y intercept of #y=x#? What is the slope and y intercept of #y=3.75#? How do you write #7+\frac{3}{5} x=y# in slope intercept form? How do you write #-5x+12=20# in slope intercept form? How do you write an equation in standard form for a line that goes through (5, –2) and (–5, 4)? See all questions in Slope-Intercept Form Impact of this question 7293 views around the world You can reuse this answer Creative Commons License