How do you solve for y in the equation $2x+2y=5$ ?

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Answer 1 · 2018-03-27T10:23:28

$y=1/2(5-2x)$

$"isolate + 2y term by subtracting 2x from both sides"$

$cancel(2x)cancel(-2x)+2y=5-2x$

. $rArr2y=5-2x$

$"divide both sides by 2"$

$(cancel(2) y)/cancel(2)=(5-2x)/2$

$rArry=(5-2x)/2=1/2(5-2x)$

How do you solve for y in the equation 2x+2y=52x+2y=5?