How do you solve #\frac { 1} { y + 3} = \frac { 7} { y - 3} - \frac { 2} { y ^ { 2} - 9}#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Lucy May 11, 2018 #y=-11/3# Explanation: #1/(y+3)=7/(y-3)-2/(y^2-9)# #1/(y+3)=7/(y-3)-2/((y-3)(y+3))# #(y-3)/((y-3)(y+3))=(7(y+3))/((y-3)(y+3))-2/((y-3)(y+3))# #y-3=7y+21-2# #6y=-3-21+2# #6y=-22# #y=-11/3# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1255 views around the world You can reuse this answer Creative Commons License