How do you solve #\frac { 2x + 3} { 8} = \frac { 3x - 4} { 7}#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Bill Jorgensen May 20, 2018 #x=53/10# Explanation: #\frac { 2x + 3} { 8} = \frac { 3x - 4} { 7}# cross multiply: #7( 2x + 3) = 8( 3x - 4) # distribute: #14x + 21 = 24x - 32# #53=10x# #x=53/10# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 1433 views around the world You can reuse this answer Creative Commons License