How do you solve #\frac{3}{4}t\leq 12#?

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Answer 1 · 2018-04-17T17:19:55

The answer is #t<=16#.

First, take #4# to the R.H.S and multiply it by #12#.

#4 * 3/4t <= 12 * 4#

#3t <= 48#

Second, divide both sides by #3#.

#(3t)/3 <= 48/3#

#t<=16#

The value on R.H.S is the answer. It actually means that #t# has values which are either equal to #16# or smaller, but no bigger than #16#.