How do you solve #h^2 = 361#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer anor277 Jan 19, 2017 If #h^2=361#, then #h=+-sqrt361# Explanation: I know that #sqrt400=20#, and thus #19^2=(20-1)(20-1)# #=# #400-40+1=361# as required............ Thus #h=+-19#. Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1378 views around the world You can reuse this answer Creative Commons License