Question

How do you solve `ln x + ln (x-2) = 1`?

Answer 1

`x = 1 + sqrt[1 + e]`

Explanation:

From `log_e x + log_e(x-2) = log_e(e)` we conclude
`log_e(x(x-2))=log_e(e)` and also
`x(x-2)=e`. Solving for `x` we obtain
`x = 1 + sqrt[1 + e]`