Question

How do you solve `lnsqrt(x+1) = 2`?

Answer 1

`=>x=e^4-1`

Explanation:

`lnsqrt(x+1)=2`
`=>log_esqrt(x+1)=2`
`=>sqrt(x+1)=e^2`
`=>(x+1)=e^4`
`=>x=e^4-1`