How do you solve ${log}_{\frac{1}{3}} p < 0$ $log_(1/3)p<0$ ?

Question

1495 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-11T16:07:39

Convert to exponent form.

${log}_{a} (n) = b \to a^{b} = n$ $log_a(n) = b -> a^b = n$

$p < {(\frac{1}{3})}^{0}$ $p < (1/3)^0$

$p < 1$ $p < 1$

Hopefully this helps!

How do you solve log13p<0log_(1/3)p<0?