How do you solve #log_3 root4(5)<=x#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Shwetank Mauria Jan 7, 2017 #x>= 0.366# Explanation: #log_3 root(4)5 <= x# can be written as #x >= log_3 root(4)5# or #x >= log_3 (5)^(1/4)# or #x >= 1/4log_3 5# or #x >= 1/4 log5/log3# or #x >= 1/4xx0.6990/0.4771# or #x >= 1/4xx1.465# or #x>= 0.366# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1288 views around the world You can reuse this answer Creative Commons License