Question

How do you solve `log_3x=9`?

Answer 1

`x=3^9`

Explanation:

When I write `log_(a)b=c`, I ask to what power I raise the base `a` tp get `b`; here `a^c=b`. By way of example, `log_(10)100=2,` i.e. `10^2=100, 10^3=1000 etc.`

Given that `log_(3)x=9`, then `x=3^9`, whatever this is it is large!