How do you solve # log_4 (x + 2) = 1/3 log_4 64#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Cesareo R. Aug 17, 2016 #x = 2# Explanation: # log_4 (x + 2) = 1/3 log_4 64# or # log_4 (x + 2) = log_4 64^{1/3}# or #x+2=64^{1/3} = 4# then #x = 2# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 1607 views around the world You can reuse this answer Creative Commons License