Question

How do you solve `log_8 2+log_8(4x^2)=1`?

Answer 1

`x=+-1`.

Explanation:

`log_8 2+log_8 (4x^2)=1`

`rArr log_8 (2*4x^2)=1`

`rArr 8x^2=8^1=8`

`rArr x^2=1`

`rArr x=+-1`

These roots satisfy the given eqn.