Question

How do you solve `log_9 x = 1.5`?

Answer 1

`:. x=27`.

Explanation:

By Defn., `log_b a=m iff a=b^m`.

`:. log_9 x=1.5 rArr 9^(1.5)=x`

`:. x=(3^2)^(1.5)`

`:. x=3^(2xx1.5)`.

`;. x=3^3`.

`:. x=27`.