How do you solve #n/3-5=12#?

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Answer 1 · 2018-04-03T17:53:54

#n=51#

Isolate #n#

#n/3-5=12#

#n/3-5+5=12+5 rarr# Add 5 to each side

#n/3=17 rarr# Multiply each side by 3

#n/3*3=17*3#

#n=51 rarr# This is the answer

Answer 2 · 2018-04-03T18:01:04

#n=51#

#n/3 -5 = 12#

#n/3 -5 +5 =12 +5 #

#n/3 =17#

#n/3 xx3 =17 xx3#

#n=51#