How do you solve rational equations #5/(3x-4)=3/(x-3)#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Abdul Sammad Feb 15, 2016 #x= -3/4# Explanation: just simply cross multiply the equation #5(x-3)# #3(3x-4)# after solving this #5x-15=9x-12# #5x-9x=-12+15# #-4x=3# #x=-3/4# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1658 views around the world You can reuse this answer Creative Commons License