Question

How do you solve `S= n/s (A+t)` for A?

Answer 1

`color(green)(A=S * s/n -t)`

Explanation:

If
`color(white)("XXX")S=n/s(A+t)`
then
`color(white)("XXX")S * s/n = cancel(s)/cancel(n) * cancel(n)/cancel(s) (A+t)`
and
`color(white)("XXX")S * s/n - t =A`

Note: if `S` and `s` are suppose to be the same variable then:
`color(white)("XXX")A=(s^2)/n-t`