How do you solve ${sin}^{- 1} x = \frac{4}{2}$ $sin^ -1x= 4/2$ ?

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Answer 1 · 2016-05-07T10:52:55

x = $sin (\frac{4}{2})$ $sin (4/2)$

${sin}^{- 1} (x) = \frac{4}{2}$ $sin^-1(x) = 4/2$ can be express into
$sin (\frac{4}{2}) = x$ $sin (4/2) = x$

Note this question must be in degree º

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