How do you solve #Sin (4theta) - Sin(6theta) = 0#?

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Answer 1 · 2016-06-27T07:47:34

#theta = (npi)/5, n=0, +-1, +-2, +-3, ...#

#sin 4theta-sin 6theta = -2 sin theta sin 5theta=0#

So sin theta = 0#, giving

#theta =npi, n=0, +-1, +-2, +-3, ..# and

#sin 5theta=0# giving #theta=npi)#, and so,

#theta=(npi )/5, n=0, +-1, +-2, +-3, ..#

The second set includes the first, as a subset.