How do you solve $sin (Arccos (7/25))$ ?

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Answer 1 · 2016-06-21T05:13:15

$+-24/25$

Use $cos(-theta)=cos theta$ .

Let $a = arc cos (7/25)$ . The $cos a = 7/25$ . a is in either 1st

quadrant or is in the fourth. Accordingly, the given expression

$sin a = +-sqrt(1-7^2/25^2)=+-24/25$ . .

How do you solve sin (Arccos (7/25))sin (Arccos (7/25))?