How do you solve the equation #log_2x=-3#?

1 Answer
Mar 22, 2018

#color(purple)(x = 1/8 = 0.125#

Explanation:

![https://mathsmethods.com.au/vce-maths-methods-lessons-cheatsheets/vce-maths-methods-logrithm-laws/](useruploads.socratic.org) From the above table,

#log_a m = n, " then " m = a^n#

Given : #log _2 x = -3#

#:. x = 2^(-3) = 1/2^3 = 1/8 = 0.125#