How do you solve the equation #x^2 - 4x = 4#?

Question

1972 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-10T19:37:34

#x^2-4x=4#

#=>x^2-4x+4=8#

#a = x#
#b = 2#

#a^2-2ab+b^2 = (a-b)^2#

#(x-2)^2=8#

#x-2 = sqrt(8)# or #-sqrt(8)#

#x_1 = sqrt(8)+2#

#x_2= -sqrt(8)+2#