Question

How do you solve the exponential inequality `2^(x+3)<=16^(4x-2)`?

Answer 1

`x ge 11/15`

Explanation:

Knowing that `16=2^4` we have

`2^(x+3) le 2^(4(4x-2))`

Here `2 > 1` then if `2^alpha le 2^beta->alpha le beta`

so

`x+3 le 16x-8->15xge 11->x ge 11/15`