How do you solve the following linear system: $14 x + 3 y = 12, 2 x - 2 y = - 8$ $14x + 3y = 12 , 2x-2y= -8$ ?

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How do you solve the following linear system: $14 x + 3 y = 12, 2 x - 2 y = - 8$ $14x + 3y = 12 , 2x-2y= -8$ ?

1 Answer

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Answer 1 · 2015-12-06T00:11:21

$x = 0$ $x=0$ , $y = 4$ $y=4$

Explanation:

$2 x - 2 y = - 8$ $2x-2y=-8$

$2 x = 2 y - 8$ $2x=2y-8$

$x = y - 4$ $x=y-4$

$14 x + 3 y = 12 \to 14 (y - 4) + 3 y = 12$ $14x+3y=12 -> 14(y-4)+3y=12$

$14 y - 56 + 3 y = 123$ $14y-56+3y=123$

$17 y = 68$ $17y=68$

$y = 4$ $y=4$

$x = (4) - 4$ $x=(4)-4$

$x = 0$ $x=0$

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How do you solve the following linear system: $14 x + 3 y = 12, 2 x - 2 y = - 8$ $14x + 3y = 12 , 2x-2y= -8$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do you solve the following linear system: 14x+3y=12,2x−2y=−814x + 3y = 12 , 2x-2y= -8?

1 Answer

Explanation:

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How do you solve the following linear system: $14 x + 3 y = 12, 2 x - 2 y = - 8$ $14x + 3y = 12 , 2x-2y= -8$ ?