How do you solve the following linear system: $2 x - 3 y = 4, 3 x + y + 2 = 0$ $2x - 3y = 4 , 3x + y + 2 = 0$ ?

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Answer 1 · 2015-11-15T18:25:42

$(-2/11, -16/11) in mathbb{Q times Q}$

$y = -3x -2$

$2x -3(-3x - 2) = 4$

$2x + 9x = 4 - 6$

$x = -2/11$

$y = -3(-2/11)-2 = (6-22)/11$

How do you solve the following linear system: 2x - 3y = 4 , 3x + y + 2 = 02x−3y=4,3x+y+2=02x - 3y = 4 , 3x + y + 2 = 0?