Question

How do you solve the following linear system `2x - 6y = 2, 3x - 8y = 2`?

Answer 1

see below

Explanation:

`We have, `2x-6y=2` or `x=(2+6y)//2` or `x=1+3y`.
The second equation is `3x=2+8y`.
Substituting the value of `x` in `2nd` equation,we get,
`3 xx(1+3y)=2+8y`
Or, `3+9y-8y-2=0`
Or, `1+y=0`
Thus, `y=-1`
Putting this value in the `1st` equation, we get,
`x=1-3` or `x=-2`