You can use substitution.
Our first step is to isolate a variable to one side, so that we can plug it in for variable wherever. What I notice first is that we have a positive xx in the second equation. Therefore, I can add 8y8y to each side in order to isolate the xx. We now have x = 2 + 8yx=2+8y.
We can plug this into the first equation. -(2 + 8y) + 3y =2−(2+8y)+3y=2. By distributing we can get -2 -8y + 3y =2−2−8y+3y=2. By solving out this equation, we end up with y = 0.8y=0.8.
Now we can plug yy back into our equation that says x = 2 + 8yx=2+8y. So we can say that x = 2 + 8(-0.8)x=2+8(−0.8). That solves out to be x = -4.4x=−4.4. We can plug this back into the original equations.
-x+3y =2 => -(-4.4) + 3(-0.8) = 2−x+3y=2⇒−(−4.4)+3(−0.8)=2
Then, 4.4 + -2.4 = 24.4+−2.4=2, and 2 =2 2=2.
