How do you solve the following linear system: $x + y = 3, 3 x + y = 4$ $x+y=3, 3x + y = 4$ ?

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How do you solve the following linear system: $x + y = 3, 3 x + y = 4$ $x+y=3, 3x + y = 4$ ?

1 Answer

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Answer 1 · 2018-03-25T05:00:16

$x = \frac{1}{2}$ $x=1/2$
$y = \frac{5}{2}$ $y=5/2$

Explanation:

Given -

$x + y = 3$ $x+y=3$
$3 x + y = 4$ $3x+y=4$

$x + y = 3$ $x+y=3$ -------------(1)
$3 x + y = 4$ $3x+y=4$ -------------(2) -----(1) $-$ $-$ (2)

$- 2 x = - 1$ $-2x=-1$
$x = \frac{- 1}{- 2} = \frac{1}{2}$ $x=(-1)/(-2)=1/2$

Substitute $x = \frac{1}{2}$ $x=1/2$ in equation (1)

$\frac{1}{2} + y = 3$ $1/2+y=3$
$y = 3 - \frac{1}{2} = \frac{6 - 1}{2} = \frac{5}{2}$ $y=3-1/2=(6-1)/2=5/2$

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How do you solve the following linear system: $x + y = 3, 3 x + y = 4$ $x+y=3, 3x + y = 4$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following linear system: x+y=3, 3x + y = 4 x+y=3,3x+y=4 x+y=3, 3x + y = 4 ?

1 Answer

Explanation:

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Impact of this question

How do you solve the following linear system: $x + y = 3, 3 x + y = 4$ $x+y=3, 3x + y = 4$ ?