How do you solve the following linear system: $y = - 3 x - 3, 4 x - 5 y = 18$ $y = - 3x - 3, 4x-5y=18$ ?

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How do you solve the following linear system: $y = - 3 x - 3, 4 x - 5 y = 18$ $y = - 3x - 3, 4x-5y=18$ ?

1 Answer

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Answer 1 · 2015-11-15T18:13:46

Solution Set $= (x, y) = (\frac{3}{19}, - \frac{66}{19})$ $=(x,y)=(3/19,-66/19)$

Explanation:

Adding $3 x$ $3x$ to both sides of 1st equation
$3 x + y = - 3$ $3x+y=-3$

Multiplying both sides of above equation by $5$ $5$
$15 x + 5 y = - 15$ $15x+5y=-15$

Adding above equation to 2nd equation of question
$19 x = 3$ $19x=3$
$x = \frac{3}{19}$ $x=3/19$

Subsituting value of x in 1st equation of question
$y = - 3 (\frac{3}{19}) - 3$ $y=-3(3/19)-3$
$y = - \frac{9}{19} - 3$ $y=-9/19-3$
$y = \frac{- 9 - 57}{19}$ $y=(-9-57)/19$
$y = - \frac{66}{19}$ $y=-66/19$

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How do you solve the following linear system: $y = - 3 x - 3, 4 x - 5 y = 18$ $y = - 3x - 3, 4x-5y=18$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do you solve the following linear system: y=−3x−3,4x−5y=18 y = - 3x - 3, 4x-5y=18 ?

1 Answer

Explanation:

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Impact of this question

How do you solve the following linear system: $y = - 3 x - 3, 4 x - 5 y = 18$ $y = - 3x - 3, 4x-5y=18$ ?